Determining the Molarity of a Sodium Hydroxide Solution The reaction between an acid and base produces a salt and water, something that you may have heard before. In the reaction that you will be investigating, the acid is potassium hydrogen phthalate (KHP), and the base sodium hydroxide (NaOH). This report is about how to standardize a Sodium Hydroxide (NaOH) solution by titrating it with pure sample of Potassium acid Phthalate (KHC8H4O4). No mL are involved in equation 1 above. In this experiment, NaOH solution will be titrated with potassium hydrogen phthalate (KHP). 925 mmol 50ml Concentration of NaOH= Discussion: NaOH is the secondary standard, therefore it’s concentration varies with time and is unstable. Calculate the moles of potassium hydrogen phthalate (KHP) Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)= 4.035 mmol KHP Step 3. KHC8H4O4 can be used for pH meter calibration or as a … 925 mmol 50 mL of NaOH= 0. NaOH, 50% – 19.4 Molar 25.0 ml of 50% NaOH weighs 37.93 gm. NaOH(aq) + KHP(aq) => Na+ + KP- + H2O(l) balanced net ionic equation 1. Then, multiply .015 L by 0.1 M NaOH----Therefore, there should be 0.0015 moles of NaOH. Calculate the molarity of the NaOH solution. The equation for this reaction will be:KHC8H4O4 (aq) + NaOH (aq) → KNaC8H4O4 (aq) + H2O (l) (Equation 1-5)Once the sodium hydroxide solution has been standardizes, it will be used to titrate 10.00mL aliquots of vinegar. Strength = 50-52%, Density = 1.52, Molecular Weight = 40.0 1 liter = 1520 gm = 775 gm NaOH (@51%) = 19.4 moles = 19.4 molar Since the number of moles of NaOH and HCl are equal all we need is the molarity of the KHC8H4O4(aq) (which you will make and calculate) and the volume of NaOH used to get to the equivalence point. (1) mols KHC8H4O4 = grams/molar mass (2)mols NaOH = mols KHC8H4O4 (since the mols ratio is 1:1 in the titration. 1.54g of KHP is equivalent to 0.00754 mol of KHP. In a titration experiment, a student finds that 25.49 mL of an NaOH solution is needed to neutralize 0.7137 g of a potassium hydrogen phthalate (KHP, a monoprotic acid with the formula KHC8H4O4). 58 / Monday, March 26, 2012 / Rules and Regulations Date of issue: 07/06/1998 Revision date: 02/21/2018 Supersedes: 10/14/2013 Version: 1.1 The equation for this reaction will be: KHC8H4O4(aq) + NaOH(aq) KNaC8H4O4(aq) + H2O (Equation 1-5) Once the sodium hydroxide solution has been standardizes, it will be used to titrate 10.00mL aliquots of vinegar. No change. This experiment was conducted to titrate NaOH with KHP. this is the reaction of KHC8H4O4 + NaOH. Sodium Hydroxide Safety Data Sheet according to Federal Register / Vol. In this case, the salt has two different metal ions, K+ and Na+. Problem: How do you calculate the mass of KHC8H4O4 (molar mass=204.44 g/mol) that reacts with 15mL of 0.16 M NaOH solution ? These answers are all perfect so I thought I'd add a more general spin. This NaOH solution is then titrated with potassium hydrogen phthalate, KHC8H4O4 or KHP solution which has been prepared by diluting 1.5 g of KHP granules in 30 mL of distilled water. Density = 1.52 gm/ml. KHC8H4O4 + NaOH -----> KNaC8H4O4 + H2O. KHC8H4O4(aq) + NaOH(aq) ( H2O(l) + NaKC8H4O4(aq) At the equivalence point equal moles of HCl and NaOH have been combined. The reaction shows that 1 mol KHC8H4O4 reacts with 1 mol of NaOH. Express this mass of KHC8H4O4 to the correct number of significantfigures and record the calculations. Given the following equation and information answer the following questions, KHC8H4O4 (aq) + NaOH(aq) > KNaC8H4O4 (aq) + H2O(l) 3. The first section is to standardize the Sodium Hydroxide by titration. Standardization of Sodium Hydroxide Solution Essay Sample. NaOH reacts with the KHP according to the following equation: NaOH + KHC8H4O4 ( H2O + NaKC8H4O4. This experiment has two sections. Variables Independent variables Mass of KHP (mKHP) Volume of KHP solution Dependent variables Volume of NaOH added [since the colour change will not happen at exactly the same volume of NaOH added … KHP is the primary standard, therefore it’s concentration is consent and stable. The phenolphthalein is an indicator that reacts to the addition of hydrogen or hydroxide ions, turning colorless with an addition of hydrogen ions and turning pink when hydroxide ions are added. What is the molarity of a NaOH solution if 26.50 mL of it is required to neutralize 0.4150 g of pure KHP? So you over titrate with the base. KHP is one of only a few stable solid acids that can be dried by warming and weighed in air. Choose an equation for the reaction between NaOH and KHP. 77, No. FREE Expert Solution Show answer 100% (174 ratings) What is the percentage of KHP in an impure sample of KHP that weighs 0.4200 g and requires 14.00 mL of 0.098 M NaOH … Since there are as many moles of KHC8H4O4 in the reaction as of NaOH( 1 mole on each), there will also be 0.0015 moles of KHC8H4O4.----Then, with the 0.0015 moles of KHC8H4O4, find out its mass by multiplying 0.0015 moles by the molecular weight of KHC8H4O4---- Aim To standardize a sodium hydroxide (NaOH) solution against a primary standard acid [Potassium Hydrogen Phthalate (KHP)] using phenolphthalein as indicator. (3 points) 4. Titration of NaOH with potassium hydrogen phthalate to determine the molarity of NaOH (Text reference for titration: 19.4) Titration is a common lab procedure that gives highly reproducible results for a variety of chemical analyses. How to solve: NaOH(aq) + KHC8H4O4 arrow H2O(l) + KNaC8H4O4(aq) 1. If exactly equivalent amounts of acid or base are used so that neither reactant is present in excess the solution is said to be at the . NaOH = 0. Fill the buret with NaOH solution. No change. Use of the information, documents and data from the ECHA website is subject to the terms and conditions of this Legal Notice, and subject to other binding limitations provided for under applicable law, the information, documents and data made available on the ECHA website may be reproduced, distributed and/or used, totally or in part, for non-commercial purposes provided … QUESTION (2) When 0.198 g of KHP is titrated with NaOH, it requires 27.80 mL of NaOH to reach the endpoint of the reaction. Sodium Hydroxide. The molar mass of KHP is approximately 204.22 g/mol. In this experiment, NaOH solution will be titrated with potassium hydrogen phthalate (KHP). KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) balanced equation. It is soluble in water. What is the molarity of a NaOH solution if 26.50 mL is required to neutralize 0.4150 g of pure KHP? The experiment is then preceded to the second part of the experiment which standardized NaOH solution is titrated the with 10 mL vinegar that has been diluted with 100 mL of distilled water. This is an acid-base reaction, which produces a salt and water. (7%) For the preparation of 1,000 mL of a standard NaOH you take 2.014 g of Potassium acid phthalate (KHC8H4O4), then titrate it with 10 mL of the prepared NaOH solution by use Phenolpthalein (C20H14O4) as an indicator. No mL involved in equation 2. Calculate the mass of KHC8H4O4 (molar mass = 204.22 g/mol) that reacts with 20.0 mLof 0.100 M NaOH. KHC8H4O4(aq) + NaOH(aq) --> KNaC8H4O4(aq) + H2O(l). 925 mmol x 1/1 = 0. Potassium acid phthalate, KHC8H4O4, or KHP, is used in many laboratories, including general chemistry laboratories, to standardize solutions of base. MM = 204.22 40.00 KHC8H4O4 + NaOH → KNaC8H4O4 + H2O Step 2. Your buret will have been properly prepared by Mrs. Atkins. KHC8H4O4 (aq) + NaOH (aq) → KNaC8H4O4 (aq) + H2O(l) KHP is an abbreviation for KHC8H4O4 and its molar mass is 204.2 g/mol. It is a waste of time to try to get the liquid level exactly on the 0.00mL line. KHC8H4O4 (aq) + NaOH(aq) ( KNaC8H4O4 (aq) + H2O(l) The net ionic equation is: HC8H4O4-1(aq) + OH-(aq) ( C8H4O4-2 (aq) + H2O(l) The reaction can be considered to proceed completely to the right. 1. KHC8H4O4 (ag) + NaOH (ag) >> Na+(ag) + K+(ag) + (C8H4O4)2-(ag) + H2O (l) QUESTION (1) Write the net ionic equation for this reaction. NaOH(aq) + KHC8H4O4(aq) = KNaC8H4O4(aq) + H2O(l) 3 The masses of each potassium hydrogen phthalate samples were converted to mols which would also reveal the mols of sodium hydroxide since the mol ratio between … The titration of 0.5523 g of KHP required 23.92 mL of an NaOH solution to reach the equivalence point. (3) M NaOH = mols NaOH/L NaOH. KHC8H4O4 is a white solid at room temperature. Calculate the moles of NaOH Moles of NaOH = 4.035 mmol KHP × (1 mmol NaOH/(1 mmol KHP)= 4.035 mmol NaOH Step 4. Write and balance the equation to confirm that.) Hi Mate The Empirical Formula For This Is C8H4KNaO4 The Systemic Name Of Which Is Potassium Sodium Phthalate. A 0.2976 g sample of KHC8H4O4 reacts with 35.05 mL of a NaOH solution in a titration. chemspider.com Is Useful If You Have Any More Problems Mate. What is the concentration of the NaOH solution? Its melting point is 295 ̊C (563 ̊F), density 1.636 g/cm3. NaOH+KHC8H4O4→Na++K++HC8H4O42−+OH− NaOH+KHC8H4O4→Na++K++C8H4O42−+H2O … KHC8H4O4 Potassium Hydrogen Phthalate KHCO3 Potassium Hydrogencarbonate KIO3 Potassium Iodate KMnO4 Potassium Permanganate KNO3 Potassium Nitrate KOH Potassium Hydroxide ... NaOH Sodium Hydroxide NF3 Nitrogen Trifluoride NH3 Ammonia NH4Br Ammonium Bromide NH4Cl Ammonium Chloride NH4NO2 Ammonium Nitrite NH4NO3